1. Get the most frequent element in a list - java 8

1.  Get the most frequent element in a list - java 8

Tools:

-JDK 8
-CoderPad/Sanbox

Solution:

import java.io.*;
import java.util.*;
import java.util.stream.Collectors;
import java.util.function.Function;
/*
 * To execute Java, please define "static void main" on a class
 * named Solution.
 *
 * If you need more classes, simply define them inline.
 */
class Solution
{
  public static void main(String[] args)
  {
     //Init list
     List<Integer> list = new ArrayList<Integer>();
     list.add(1);
     list.add(3);
     list.add(1);
     list.add(3);
     list.add(2);
     list.add(1);

     int most=mostFrequentElement(list);
     //Print result
     System.out.print("The most frequent element in list is:"+most);
  }
  //Method that return the most frequent element in array
  public static int mostFrequentElement(List<Integer> list)
  {
    //Group the list in a map by the number of appareance
    Map<Integer,Long> group = list
                             .stream()
                             .collect
                              (
                                Collectors
                                .groupingBy
                                (
                                   Function.identity()
                                  ,Collectors.counting()
                                )
                             )
    ;
  
    Map<Integer, Long> finalMap = new LinkedHashMap<>();
    //This method does not mutate the original map.
    //Put in first place the element which have more appearances than the others one based on the previous group
    group
   .entrySet()
   .stream()
   .sorted
   (
     Map
     .Entry
     .<Integer,Long>comparingByValue()
     .reversed()
   )
   .forEachOrdered(e -> finalMap.put(e.getKey(),e.getValue()));
   
   return finalMap.entrySet().stream().findFirst().get().getKey();
 }
}

Comment:

Leave a comment if you have a doubt or you have a better solution, also if you have any suggestion